Determine the range of the function -5+5cos squared (x)?

Answer 1

[-5 , 0]

cos^2 x runs between 0 an 1 inclusive, so 5cos^2 x runs between 0 and 5 inclusive. Subtract 5 (to get your function), and the result runs between -5 and 0, inclusive.

Answer 2

The range of cos x is -1 to 1. So the range
of cos² x is 0 to 1 as each negative value
becomes positive when squared.
So the range of -5+5 cos² x is -5 to 0.

Answer 3

The range of a function are all the possible values of the function.

The cos function has a max value of +1, zero for 90 deg and -1 minumum. Thus 5 cos^2 (x) can have values from -5 to +5. Add these values to -5 and we get, range is from -10 to 0.

Hope this helps. If you have a TI 83/84 etc, you can graph this function and visually see the range.

Mike R

Answer 4

the range of cos squared (x) is 0 to 1. The amplitude of 5 makes this range 0 to 5. then, adding a -5 causes the range to be from -5 to 0.

Answer 5

The range of cosine is -1 to +1.
Same for cos squared.
Therefore this function ranges between -10 and 0

Answer 6

If you mean f(x) =5cos(x)^2 - 5
then:

cos(x) has been vertically expanded by 5 units.
cos(x) has been vertically shifted 5 units down.
the range would have to be [-5 , 0]
the domain for fun is xER.

Answer 7

You plug in each fee in {x}. you're meant to position in writing the decision as a collection: {eleven, -a million, -5, -a million} shows the fee of y you get for each fee of x. would nicely be written as only {eleven, -a million, -5} because y=-a million is repeated