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Ok well, It says: "write each equation in standard form, then solve"
4=-5n+6n^2

2007-04-05 14:04:18 · 3 answers · asked by Poseidon 2 in Science & Mathematics Mathematics

3 answers

Standard form, by definition is the form
ax^2 + bx + c = 0, for constants a, b, and c. All we have to do is rearrange the equation.

4 = -5n + 6n^2

First, let'ss rearrange the terms on the right hand side in descending order of n.

4 = 6n^2 - 5n

Now, move 4 to the right hand side.

0 = 6n^2 - 5n - 4

As you can see, now it is in standard form. Factor accordingly.

0 = 6n^2 - 8n + 3n - 4
0 = 2n(3n - 4) + (3n - 4)
0 = (3n - 4)(2n + 1)

Equate each factor to 0.

3n - 4 = 0
2n + 1 = 0

n = {4/3, -1/2}

2007-04-05 14:15:01 · answer #1 · answered by Puggy 7 · 0 0

0=6n^2-5n-4 (standard form, the higher degree, n squared, comes first)
0=(3n-4)(2n+1) (factor the previous equation)
Set the factors to 0,
n=4/3, -1/2

2007-04-05 21:13:26 · answer #2 · answered by justagirl 3 · 0 0

6n^2-5n-4=0

(3n-4)(2n+1)=0
3n-4=0
2n+1=0
3n=4
n=4/3
2n=-1
n=-1/2

answer n=4/3 or -1/2

2007-04-05 21:09:59 · answer #3 · answered by Dave aka Spider Monkey 7 · 1 0

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