the sum of the squares of two numbers is 4 less than the sum of 100+one half hundred. What are the 2 numbers?

Answer 1

Rather than just provide the answer, here is how I solved the problem:

x² + y² = (100 + 100/2) - 4

x² + y² = (100 + 50) - 4

x² + y² = 146

Trial and error to find x and y

12² = 144; 146 - 144 = 2
11² = 121; 146 - 121 = 25 (wow, 5² = 25)

The two numbers are 11 and 5.

Answer 2

Let: x = 1st number
y = 2nd number

x^2 + y^2 = 100 + (100/2) - 4
x^2 + y^2 = 100 + 50 - 4
x^2 + y^2 = 146

Since there is no other information given to form another equation, just see what 2 perfect squares sum to 146 by trial and error.
x^2 + y^2 = 121 + 25 --> get the square roots to get the numbers:
11 and 5

Answer 3

11 and 5

11^2 + 5^2 = 121 + 25 = 146 = 100 + 0.5x100 - 4

Answer 4

11 and 5


11^2 + 5^2 = 150-4
121 + 25 = 146