x^2 = 3 + 2x How do I get the x^2 to the other side? Then how do I factor it? I am so confused!?

Answer 1

Subtract 2x and 3 from both sides.

x^2 - 2x - 3 = 0

(x - 3)(x + 1) = 0

Let each factor = 0

x - 3= 0, x = 3

x + 1 = 0, x = -1

Answer 2

Well, it turns out that you want to keep x^2 on that side, since subtracting x^2 from both sides (which is usually done) will give you a -x^2 on the right hand side. Rather, you want to move every thing over to the left hand side; subtract 3+2x from both sides to get
x^2 - 2x - 3 =0
Factoring this requires practice, since we seek two integers whose product is -3 and when added together, will give -2. In this case, the answer isn't too hard, so we can come up with (x+1)(x-3)=0
The roots are x= -1 and x= 3. They work!!

Answer 3

easy, x^2=3+2x so, subtract x^2 from both sides.
you will get 3+2x-x^2 =0
now you can factor the left side like this
3+2x-x^2= (x-3)(-x-1)
so (x-3)(-x-1)=0 this can only happen when x-3=0 or -x-1=0
thus x can be either 3 or -1.
get it?

Answer 4

x^2 = 3 + 2x

1) You can change sides by changing signs (add by subtraction - multiplication by division)

So you'll have: 0 = -x^2 + 2x + 3 or: x^2 - 2x - 3 = 0

2) You can also subtract x^2 from both sides

x^2 = 3 + 2x
- x^2 = -x^2

add and you'll have: 0 = -x^2 +2x + 3 (same result)

Lets take x^2 - 2x - 3 = 0
Then you apply the quadratic formula:

ax^2 + bx + c = 0 when x = [-b +- Sq Rt(b^2 - 4ac)] / 2a

[2 +- Sq Rt (4 + 12)]/2 =
(2 +- 4)/2
A) x = 3
B) x = -1

Check:

x^2 - 2x - 3 = 0

A) x = 3
3^2 - 2*3 - 3 = 0
9 - 6 - 3 = 0 Checks

B) x = -1
-1^2 - (2*-1) - 3 = 0
1 + 2 - 3 = 0 Checks too.

Answer 5

All you have to do is substract it but if you will be factoring it will easier to subtract everything else and move it to the left so then the problem would be..
x^2 - 2x - 3.

To factor it you make 2 sets of parentheisis...
( )( )

Next you put x in both (so it would equal x^2)
(x )(x )

Next since it is -2 and -3 you would have to know that whatever the two numbers are....
a. one is negaitve and one is positive
(because a negative plus a positive equals a negative)

b. the bigger number is negative since it has to add up to equal -2

c. the other number is positive and the product of the negative and positive number equals -3

The answer would have to be .....
(x-3)(x+1)
because -3 times 1 = -3
and -3 + 1 = -2
x-3=0 x = 3

x+1=0 x = -1

hope it helped

Answer 6

it would be x^2-2x-3= 0 when u get it to the other side, then factor it... = (x-3)(x+1)...so u get x= +3, -1

Answer 7

actually, i'd put the 3 + 2x to the other side. it doesn't matter, as long as you have everything equal to zero in this case.

so, subtract the 3 + 2x from both sides, giving you:
x^2 - (3+2x) = 0
so, continuing:
x^2 - 2x - 3 = 0
now factor it out.
try it yourself before scrolling down













































You shoulda gotten (x-3)(x+1). If not, look at the section in your book again.

Answer 8

x^2 - 2x - 3 = 0

(x + 1)(x - 3) = )

x = -1 or x = 3

Answer 9

change sign when you move

x^2 - 2x - 3 = 0

spot that 3-1 = 2 and 3*1 =3

(x+1)(x-3) = 0

so x = 3 or -1

Answer 10

you move all terms to one side and equate it to zero..

which you will get x^2-2x-3=0

(x-3)(x+1)= 0
x = 3, -1