I really tried and I may have it right, but I am not sure. Here is the problem:
AlCl3 + AgNO3
2007-04-05 12:54:49 · 7 answers · asked by Holy Macaroni! 6 in Science & Mathematics ➔ Chemistry
1 AlCl3 + 3 AgNO3 ==> 3 AgCl + 1 Al(NO3)3
Aluminum: 1, 1
Chlorine: 3, 3
Silver: 3, 3
Nitrogen: 3, 3
Oxygen: 9, 9
2007-04-05 13:01:17 · answer #1 · answered by Eric 6 · 0⤊ 0⤋
AlCl3+AgNO3 = AgCl + Al(NO3)3
To balance the equation
AlCl3+3AgNO3 = 3AgCl + Al(NO3)3
Driving force for the reaction is the precipitation of the insoluble AgCl. The Al(NO3)3 will stay in ionic form in the solution
2007-04-05 20:09:20 · answer #2 · answered by ktrna69 6 · 0⤊ 0⤋
AlCl3 + AgNO3 ---> AlNO3 + AgCl3
i think thats right... im not for sure... been a while since ive done that kind of problem...
2007-04-05 20:06:44 · answer #3 · answered by tweetybird6990 1 · 0⤊ 0⤋
So that will be AlCl3 + 3AgNO3 ---> Al(NO3)3 + 3AgCl
I should be right, but 5 months of vacation from school may have rotted my brain, so double check against your answer...
2007-04-05 20:03:48 · answer #4 · answered by GreyLily 2 · 0⤊ 0⤋
AlCl3 + 3AgNO3 .....>3AgCL + Al (NO3)3
2007-04-05 20:37:33 · answer #5 · answered by gangico 3 · 0⤊ 0⤋
... and the AgCl will precipitate out.
2007-04-05 20:07:38 · answer #6 · answered by gp4rts 7 · 0⤊ 0⤋
uh...are you looking for....
AlNO3 + AgCl3
2007-04-05 20:04:10 · answer #7 · answered by Anonymous · 0⤊ 0⤋