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a rubber ball whose mass is 3.5 kg is moving with a velocity of 34.4 at 210 degrees meters per second. it collides with and embeds itself in a 2.4 kg block of clay that is moving with a velocity of 12 at 130 meters per second. what is the velocity of the combined mass just after the impact?

2007-04-05 12:26:09 · 2 answers · asked by mandy 1 in Science & Mathematics Physics

2 answers

Yes. This is a conservation problem. The sum of velocities and masses before the collision must be the same as the sum of velocities and masses afterward. The mass x velocity of the brick before the collision + the mass x velocity of the ball before the collision = the combined mass of the ball and brick x the final velocity of the combined mass after the collision.
Conservation of momentum: m1*v1 + m2*v2 = m3*v3
where m3 = (m1 + m2). Substitute and solve for v3.

2007-04-09 02:05:58 · answer #1 · answered by sparc77 7 · 0 0

Break it down. Remember the old algebra questions. This train left the station at this time and speed, and the other train left this station at this time and speed.

2007-04-05 19:34:23 · answer #2 · answered by joeson73 2 · 0 0

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