18. -15x3y3
-20xy4
24. 4x - 28
5x - 35
36. 4r2 - 25s2
2r2 + 3rs - 20s2
50. Geometry. The volume of the box is represented by (x2 + 5x + 6)(x + 5). Find
the polynomial that represents the area of the bottom of the box.
2007-04-05 12:17:15 · 5 answers · asked by Dave 4 in Science & Mathematics ➔ Mathematics
(-15x3y3)/(-20xy4)
= 3x^2/4y
(4x - 28)/(5x - 35)
=4(x-7)/5(x-7) = 4/5
(4r2 - 25s2)/(2r2 + 3rs - 20s2
= [(2r-5s)(2r+5s)]/[(2r-5s)(r+4s)]
= (2r+5s)/(r+4s)
Geometry. The volume of the box is represented by (x2 + 5x + 6)(x + 5). Find the polynomial that represents the area of the bottom of the box. The area must be represented by the polynomial x^2 + 5x + 6 and the height by x + 5.
2007-04-05 12:37:27 · answer #1 · answered by ironduke8159 7 · 0⤊ 0⤋
(-15x^3y^3)/(-20xy^4)
(-15)/(-20) = 3/4
x^3/x = x^2
y^3/y^4 = 1/y
(-15x^3y^3)/(-20xy^4) = 3x^2/4y
(4x - 28)/(5x - 35) = [4(x - 7)]/[5(x - 7)] = 4/5
(4r^2 - 25s^2)/(2r^2 + 3rs - 20s^2)
The polynomials can be factored
4r^2 - 25s^2 = (2r + 5s)(2r - 5s) {difference of 2 squares)
2r^2 + 3rs - 20s^2) = (2r - 5s)(r + 4s)
The fraction is now
[(2r + 5s)(2r - 5s)]/[(2r - 5s)(r + 4s)]
(2r + 5s)/(r + 4s)
See the factoring lesson at the link below
2007-04-05 12:46:31 · answer #2 · answered by Anonymous · 0⤊ 0⤋
18.)
(-15x^3y^3)/(-20xy^4)
(-15/-20) * x^(3 - 1) * y^(3 - 4)
(3/4) * x^2 * y^(-1)
ANS : (3x^2)/(4y)
--------------------------------------
24.)
(4x - 28)/(5x - 35)
(4(x - 7))/(5(x - 7))
ANS : (4/5)
-------------------------------------
36.)
(4r^2 - 25s^2)/(2r^2 + 3rs - 20s^2)
((2r - 5s)(2r + 5s))/((r + 4s)(2r + 5s))
(2r - 5s)/(r + 4s)
-------------------------------------
50.)
(x^2 + 5x + 6)(x + 5)
(x + 3)(x + 2)(x + 5)
Width = (x + 2)
Length = (x + 3)
Height = (x + 5)
ANS : x^2 + 5x + 6 would probably be my answer, but it really depends on what the bottom measurements are
other answers could be
x^2 + 8x + 15 or x^2 + 7x + 10
2007-04-05 13:01:30 · answer #3 · answered by Sherman81 6 · 0⤊ 0⤋
3x^2 / 4y
4(x-7) / 5(x-7)= 4/5
(2r-5s)(2r+5s)
-------------------
(2r-5s)(r +4s)
2r+s /r+ 4s
x^3+5x^2+5x^2+25x+5x+30
x^3+10x^2+30x+30
2007-04-05 12:37:58 · answer #4 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
detect an prolonged-widespread denominator if then multipy the two binomials interior the denominators jointly....yet remember that as a fashion to maintain a fragment equivalent....Watever u do to the backside u might desire to do to the utmost
2016-10-21 03:30:29 · answer #5 · answered by ? 4 · 0⤊ 0⤋