Relative rate of change?

0 ⤊

Find the relative rate of change and evaluate t = 6

f(t) = 500e^(0.35*sqrt(t))

2007-04-05 12:09:52 · 2 answers · asked by benji davis 1 in Science & Mathematics ➔ Mathematics

f(t) = 500e^(0.35√t)
f'(t) = 500e^(0.35√t) * 0.35/2√t
= 87.5 e^(0.35√t) / √t

f'(6) = 87.5 e^(0.35√6) / √6
= 84.19

2007-04-05 12:11:55 · answer #1 · answered by smci 7 · 0⤊ 0⤋

f(t) = 500e^(0.35*sqrt(t))
f(t) = 500[e^0.35 + e^sqrt(t)]
f'(t)= 500[e^0.35 +e^sqrt(t)/2sqrt(t)]
f'(6) = 1891.66

2007-04-05 19:25:50 · answer #2 · answered by ironduke8159 7 · 0⤊ 1⤋