Hi guys.... i got a math question?

Question

Good evening guys
I know how to do these problems, but when i come across fractions, i am stuck.... i need help please
1. Use elimination to solve
x/3 +4y = 30
2x - y = 5

2. Use elimination to slove :
6y - y/4 = -9
3x +2y = -30

Thank you !!!

oops
this is the second question
6x - y/4 = -9
3x + 2y = -30
appreciate y'all.

Answer 1

1. X=6 Y=7
x/3+4y=30 2x-y=5
3(x/3+4y=30) 12(2x-y=5)
x+12y=90 + 24x-12y=60
25x=150
x=6
plug x in to get y

2. X=-2 Y=-12
6x-y/4=-9 3x+2y=-30
8(6x-y/4=-12)
48x-2y=-72 + 3x+2y=-30
51x=-102
x=-2
plug x in to get y

Answer 2

Elimination by addition method

x/3 + 4y = 30- - - - - Equation 1
2x - y = 5- - - - - - - - Equation 2
- - - - - - - - -

Clear the fraction equation 1

x/3 + 4y = 30

3(x/3) + 3(4y) = 3(30)

x + 12y = 90
- - - - - - - - - -

x + 12y = 90
2x - y = 5
- - - - - - - - -

Multiply equation 2 by 12

2x - y = 5

12(2x) - 12(y) = 12(5)

24x - 12y = 60

- - - - - - - - - - - --
Elimination of y

x + 12y = 90
24x - 12y = 60
- - - - - - - - - - -
25x = 150

25x / 25 = 150 / 25

x = 150 /25

x = 6

Insert the x value into equation 1

- - - - - - - - - - - - - - - - - - - - - - - -

x/3 + 4y = 30

6 / 3 + 4y = 30

2 + 4y = 30

2 + 4y - 2 = 30 - 2

4y = 28

4y / 4 = 28 / 4

y = 28 / 4

y = 7

Insert the y value into equation 1

- - - - - - - - - - - - - - - - - - - - - - - - -

Check for equation 1

x/3 + 4y = 30

6/3 + 4(7) = 30

2 + 28 = 30

30 = 30

- - - - - - - -

Check for equation 2

2x - y = 5

2(6) - 7 = 5

12 - 7 = 5

5 = 5

- - - - -

The two equations balance

The solution set { 6, 7 }

- - - - - - - - - - s-

Answer 3

k I can help...well first u wanna get rid of the fraction..x/3 so multiply both sides by 3...so x/3(3) +(3)4y=30(3)
so ur left with x+4y=90...then u have to carry on cuz u said u know the rest--> x+12y=90
2x-y=5
multiply the bottom equation by 12 so u can eliminate the y
ur left with 24x-12y=60
x+12y=90
then u have to add the rest...
25x=150
x=6

now substitute: 2(6)-y=5
12-y=5
-y= -7
-y(-1)=-7(-1)
y=7




-->y= 7
-->x= 6

and check ur answers:)

Answer 4

The easy way to deal with fractions is to just multiply through by something big enough to clear them out. In the first problem, just multiply the first line by 3.
x + 12y = 90
2x - y = 5

Then, since we're using elimination, double the first row.
2x + 24y = 180
2x - y = 5

Subtract the second row from the first:
25y = 175
so y=7. Plug that into one of the equations and you'll get x=6.

Do the second problem the same way... just multiply the first row by four, and then solve normally.

Answer 5

22

Answer 6

multiply the top by 3 so u remove the fraction:
1X+12y=30
multiply the bottom by 12 so u eleimiate the y
24x-12y=60

add to get 25x=90

x= 3.6


multiply the top by -4 to remove fraction!
24x+1y=36

multiply the bottom by -8
-24x-16y=240

ADD: -15y=276

y=18.4

Answer 7

remember the > image.... 2 could be incorrect. As fixing with 2 gives you 0; 0 isn't > 0. the respond it looks like could be x < 2 and x > 4. in basic terms remember your extra desirable than would not contain equivalent to. If it did contain equivalent to you may desire to assert 2 and four could be valid aspects as properly. Edit: in basic terms had to function the "as properly" area

Answer 8

for the first one y=7 x=6

for the second one i cant use elimination maybe u typed it wrong

Answer 9

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Answer 10

hey grace ur right