what is the total measure [in degrees] of the interior angles of a 6 sided polygon?
2007-04-05 11:14:11 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Caculatint the interior angles of a polygon
n = number of sides
180(n - 2) =
180(6 - 2) =
180(4) =
720 degrees
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2007-04-05 13:06:41 · answer #1 · answered by SAMUEL D 7 · 0⤊ 0⤋
The formula to give you the degree value of each internal angles of a n-gon is:
180(n - 2) / n
But since you want the total internal angle value, you can remove the division by n. In this case, n is 6. So...
180(6 - 2)
180(4)
720
720 degrees is the total measure of interior angles. Divide by 6 gives you 120 degrees for each angle (for a regular hexagon)
2007-04-05 18:19:55 · answer #2 · answered by Bhajun Singh 4 · 0⤊ 0⤋
Sum of interior angles = 180(n-2) where n = number of sides.
So for 6 sides, sum = 180(6-2) = 720 degrees.
2007-04-05 18:19:49 · answer #3 · answered by ironduke8159 7 · 0⤊ 0⤋
interior angle is always 180(n-2)/n
where n is the number of sides (obviously greater than 3)
so for 6 you plug in to get
180(4)/6 = 120 degrees.
2007-04-05 18:18:37 · answer #4 · answered by NArchy 3 · 0⤊ 2⤋
180(n-2)
180 (6-2) = 720 degrees.
so the total is 720 degrees.
each interior anlge is 120 degrees.
2007-04-05 18:23:23 · answer #5 · answered by 7 · 0⤊ 0⤋
1080 degrees
2007-04-05 18:19:02 · answer #6 · answered by BumbleBee 1 · 0⤊ 1⤋
I dunno but rememeber that all degrees in a polygon add up to 360 degrees. Or wait, is that a quadrilateral that I'm thinking of?
2007-04-05 18:19:24 · answer #7 · answered by ? 2 · 0⤊ 1⤋