2007-04-05 11:12:33 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
pv=nRt
n=(pv)/Rt
T= 25 + 273 = 298K R=.0821 for pressure at atm
n=(.75atm x 12.5L)/(.0821 x 298K) = 0.383 mol
2007-04-05 11:41:14 · answer #1 · answered by coldfire 1 · 0⤊ 0⤋
by using fact the quantity does not replace (cylinder with fixed quantity) based on the equation PV=nRT the place V, T and R are consistent for the two instruments of situations, Use the equation P1/n1T1 = P2/n2T2 and remedy for n2 to get the moles interior the 2d subject. bypass multiplying you get P1n2=P2n1 and dividing the two facets by ability of P1 you get n2 = n1 (P2) / (P1) P1=150 atm; P2=13 atm n2=150/13=11.5 mol. Argon has an molar mass of 39.948, so grams = 11.5 x 39.948 = 461 g
2016-11-26 21:17:18 · answer #2 · answered by ? 4 · 0⤊ 0⤋
I won't answer your question for you, but I will give you the tools to answer it yourself. The ideal gas equation is (P)ressure * (V)olume = (n)umber of moles * (R Gas constant of 0.0821) * (T)emperature in Kelvin.
This means taht you can find the number of moles via the following
n = (PV)/(RT)
2007-04-05 11:17:44 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Make sure you use the correct value for "R". I this case, with atm., liters, moles and K, the correct "R" is 0.0821
2007-04-05 11:17:32 · answer #4 · answered by reb1240 7 · 0⤊ 0⤋
(.75)(12.5)= n(.08206)(25+273.15)
n=0.383 moles of Hydrogen gas
2007-04-05 11:17:34 · answer #5 · answered by NArchy 3 · 0⤊ 0⤋
.75*12.5=n*.0821*298
n=approximately .383 moles
2007-04-05 11:24:44 · answer #6 · answered by Jimmy 2 · 0⤊ 0⤋
Since pressure changes with temperature, so long as we know the pressure, then temperature is irrelavent
2007-04-05 11:16:49 · answer #7 · answered by Anonymous · 0⤊ 1⤋
pv=nRT
T is Kelvins
2007-04-05 11:16:02 · answer #8 · answered by Anonymous · 0⤊ 0⤋