A sealed rectangular container 6 cm by 12 cm by 15 cm is sitting on its smallest face.?

Question

It is filled with water up to 5 cm from the top. How many cm from the bottom will the water level reach if the container is placed on its largest face?

Answer 1

so initially its sitting on the 6 by 12 side and the water is filled 5 from the top, meaning its 10 deep...so the volume of the water is 6*12*10 = 720 cm^3 (mL)

when placed on the largest face, 12 times 15 the height will be volume multiplied by the known dimensions: namely,
720/(12*15) = 4 cm
the water will be 4 cm high, 2 cm from the top

Answer 2

Part 1:
The smallest face is 6 x 12. Since the water is 5 cm from the top, it is filled up to a height of 10 cm. So the volume of water is 6 x 12 x 10 = 720 cm^3

Part 2:
The largest face is 12 x 15, which has an area of 180 cm^2. 720 cm^3/180 cm^2 = 4 cm. The water will fill the box to a height of 4 cm

Answer 3

the smallest face is 6 by 12, which is 72 cm^2
the volume of water is 5cm(72cm^2)= 360 cm^3
the largest face is 12 by 15, which is 180cm^2
(360cm^3)/(180cm^2) = 2cm
so the water comes up 2 cm