Write the equation of the line y-7= 4(x-2) in slope-intercept form.?

Answer 1

y - 7 = 4(x - 2)

y - 7 = 4x - 8

y - 7 + 7 = 4x - 8 + 7

y = 4x - 1

- - - - - - - - -s-

Answer 2

Slope-intercept form is y=mx+b with m as the slope and b as the y-intercept.

y-7=4(x-2)
y=4x-8+7
y=4x-1 (slope=4, intercept=-1)

Answer 3

Your all forgetting that slope is a fraction. Instead of having 4 as just a plain number, the slope would be 4/1. Rise four and over 1.

Answer 4

Slope-intercept form is the y=mx+b format, so it's pretty simple to get there...

y-7=4(x-2)
y-7=4x-8
y=4x-1

Good Luck!

Answer 5

ok i'm no longer a extreme college maths instructor, so it could pay to envision with somebody else! yet on the time of me typing I look all you have (optimistically somebody else will come alongside!), so here is going... on your graph, positioned a dot at 2,2 (ie, 2 squares throughout and a pair of squares up). positioned yet another dot at 7 on the y-axis. connect them. you will see that the line is going down 5 squares for each 2 squares it is going throughout to the wonderful. by using fact it is going DOWN 5 squares it truly is "-5". by using fact it is going 2 to the wonderful it truly is "2". (Left could be "-2"). so which you have the "-5/2" section. The +7 is purely the place it intercepts the y-axis. And an intercept equation is what you go with. So positioned "y=" at first and "+7" on the top. Now you have "y=-5/2+7". i'm specific there's a greater ideal clarification!

Answer 6

y=4x-8+7
=>y=4x-1

Answer 7

y=4x-1

Answer 8

y-7=4x-8
y=4x-1