How can you solve x for ln x=2.41?
Please explain to me how do you find the answer, thanks.
2007-04-05 08:49:31 · 4 answers · asked by starsgirl021687 2 in Science & Mathematics ➔ Mathematics
e and ln cancel each other out, so take the e of both sides.
e^(ln x) = e^2.41
x = e^2.41
2007-04-05 08:55:08 · answer #1 · answered by Mathematica 7 · 0⤊ 0⤋
The base of a natural log is 'e'.
e=2.718 approx
ln(base e) x = 2.41
basic rule of logs:
ln x = y can be converted to:
e^y=x
so....
ln x=2.41
e^2.41=x
2.718^2.41=x
11.13=x
2007-04-05 15:54:44 · answer #2 · answered by Anonymous · 0⤊ 0⤋
note that e^ (lnx) = x . for all x > 0.
ln x=2.41 => e^(lnx) = e^2.41 => x = e^2.41
2007-04-05 15:53:08 · answer #3 · answered by gjmb1960 7 · 0⤊ 0⤋
ln(x) = 2.41
just inverse ln both sides, which is e^, and you get
x = e^(2.41) or about 11.134
2007-04-05 18:32:31 · answer #4 · answered by Sherman81 6 · 0⤊ 0⤋