Please help me with logarithmic question?

Question

f(x)=log(base 10)(x)
How do you find x when f(x)=6 and f(x)=-4?
How do you solve that?

Answer 1

so
6 = log x
10^6 = 10 ^ (log x)..... 10 ^ log reduces to 1
10^ 6 = x
same method for the other one

Answer 2

From the definition of the logarithm:
f(x) = log(x) implies that 10^f(x)=x

f(x)=6 ==> x=10^6=1,000,000

f(x)=-4 ===> x=10^-4 = 1/10^4 = 0.0,001

Answer 3

just exchange f(x) in your first equation for 6 and for 4
equation a) 6 = log (base 10) (x)
euqation b) 4 = log (base 10) (x)
by the definition of log (base 10)
equation a) x = 10 ^ 6= 1000000
equation b) x = 10 ^ 4 = 10000

Answer 4

okay since f(x)=6 we can say
6=log(base 10)(x)
then we know that 6 is
the exponent of 10 so 10^6=x
that equals 1,000,000

when f(x)=-4 we can say
-4=log(base 10)(x)
so 10^-4=x
that equals 10,000

if its not right im sorry im trying to do the best i know out of my math book

Answer 5

Think of it this way... 10 to what power = X?

so...
6=log10(x)
10 to the 6th power = X
10^6 = 1,000,000

-4 = log10(x)
10 to the -4th power = x
10^-4 = 0.0001

Answer 6

f(x) = log(10)x

6 = log(10)x

when given y = log(b)x, it becomes x = b^y

x = 10^6
x = 1000000 or 1 * 10^6

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x = 10^(-4)
x = .0001