How do you make a 10mM stock solution out of a 1gram of a chemical?

Question

i believe its mw = 786.36

Answer 1

First you've got to figure out how many moles you'd need

10mM = 10*10-3M/L = 10-2 moles/liter

1gram of 786.36MW = 0.0012717 moles

So how MUCH of 10mM could we make out of this

0.0012717mole/xL = 10-2moles/L ==> x = 0.127L

take your 1 gram and dissolve it in 127 ml H20 to get a 10mM solution

Answer 2

Find out its true molar mass.

If that is correct 1 gram = 1.27 X 10-3 mol

Dividing moles by 0.01 M gives 0.127 L.

So, dissolving your 1 gram in 127 mL of water or buffer will give a 10 mM solution. If that's too much, you could weigh out 100 mg and dissolve that in 12.7 mL.

Answer 3

ordinary way for combination q's ??????????? A = 3% capability B = 15% capability T = objective = 6% capability ???????????????????????????????? the ratio of A & B needed would be in inverse share to distance from T ???????????????????????????????? A:B = (15 - 6) : (6 - 3) = 9:3 = 3:a million ans: ?? A: (3/4)*one hundred = seventy 5 gal of three% capability B: (a million/4)*one hundred = 25 gal of 15% capability