chemistry question???? about molarity?

Question

ok, so we have a solution of NaCl, that is 50.grams, and 0.5Liter. what is the volume that we need to make a 1.3L of 0.100 molarity NaCl solution?

plz show the steps

Answer 1

NaCl (Mw = 58.5 g/mole)

50 g NaCl = 0.855 moles in 0.5 liter = 1.71 M NaCl

you want 1.3L of .1M NaCl

or you want .13mole/1.3liter = .1M

0.13 mole = xL * (1.71mole NaCl/liter) ==> x = 0.076 L

or 76 ml of 1.71M NaCl soln diluted to 1.3 L will give 0.1 M NaCl

Answer 2

50g and 0.5liter means 100g/L

to make a solution of 0.1m as the molecualar weight of NaOH is 40 you need 4gNaOH
to make 1.3L you need 40*1.3 =5.2g

so you need 5.2/100 liter of your solution

this is 0.052L = 52 cm^3

Answer 3

50grams NaCl in 0.50Lts is equivalent to 100Grams in 1.0 lts.So the molarity of the solution is 100/58.5 M(58.5 is the molecuar weight of NaCl)
To make 1.3 L of 0.100M NaCl:
M1V1 = M2V2
1.3*0.100 = 100/58.5 *V2
we have to calculate V2;

or V2 = 1.3*0.1/100/58.5;

or V2 = 1.3*0.1*58.5/100;

or V2 = 7.605/100 L;

or V2= 0.07605L = 76.05 Ml

Therefore 76 ml solution will be required.

Answer 4

Ans
40*1.3 =5.2g
=5.2/100 per liter
=0.052
=52 cc