Quadratic equations with use of square root formula?

Question

Here's my problem:
x^2-2x+1=0

I need to solve this using the quadratic formula.

Answer 1

Quadratic Formula

x = - b ± √b² - 4ac / 2a

x² - 2x + 1

a = 1

b = - 2

c = 1

x = - (- 2) ± √(- 2)² - 4(1)(1) / 2(1)

x = 2 ± √4 - 4 / 2

x = 2 ± 0 / 2

x = 2 / 2

x = 1

- - - - - - -s-

Answer 2

Ok you know the quadratic formula.
-(b) [+or-] sqrt(b^2-(4)(a)c)
x {the variable you are solving for}= ------------------------------------
2(a)
now you have your equation x^2-2x+1=0 {have equation set to zero so you can use the formula}
I like to use a little trick to get rid of the 2 in front of the a on the bottom. Thus you get your a now=a/2,b now =b/2, and c now =c/2.You times your whole equation by (1/2) so then whatever your a is you get 2(a/2).
In your equation your a (with the trick would be) (1/2) because you have only a one in front of your x^2. Then your b would be (-2)/2 {have -2 from the minus 2x}, and your c would be (1/2). Now just plug in those values where you see the corisponding letter in the equation above.

Answer 3

x^2-2x+1=0
x = {2 +/- sqrt(4-4)}/2
x = 2/2 = 1
1 is a double root of the given equation.

Answer 4

a million] sqrt2x^2 -x - sqrt2 = 0 x = [a million +/- sqrt[a million + 4*2]]/2sqrt2 x = [a million +/- sqrt 9]]/2sqrt2 x = 2/sqrt2 or -a million/sqrt2 so factors are [x - sqrt2][x + a million/sqrt2] 2] sqrt2x^2 + x - 10sqrt2 x = [-a million +/-sqrt [a million + 80]]/2sqrt2 x = [-a million +/- 9]/2sqrt2 x = -5/sqrt2 or 4/sqrt2 x = -3.fifty 4 or 2.80 3 factors are [x + 3.fifty 4][x - 2.80 3] = 0 have left one in root style and the different in decimal you could decide for

Answer 5

a=1, b=-2, c=1. Plug them in the formula.

Answer 6

Another way to do these is:

x^2 + bx + c = 0

Find two numbers, d and e, such that d+e=b and d*e=c. Then these goes into the equation:

(x+d)(x+e)=0

In this case, -1 -1 = -2 and (-1)(-1) =1

(x-1)(x-1)=0
x=1 (m2)

Answer 7

x1,2 = [2 +- sqrt((-2)^2 - 4*1*1)]/2 = [2 +- sqrt(4 - 4)]/2 = 2/2 = 1

Answer 8

x = {-(-2) +- sqr[(-2)^2 - 4(1)(1)]}/2(1)
= {2 +- sqr[4 - 4]}/2 = 1 for both roots