absolute value of -6 is 6 and absolute value of 2 is 2
so.. -6 - 2
-6 + -2
= -8
it shoulf be minus eight or if you mean -(-6-2) it would be plus eight and thanks for telling me about the vertical lines because first i thought it is -1-61-121 which would equal -183
You can put absolute value line by pressing the shift key and the back slash at the same time.
I wonder who you will pick as best.......
2007-04-05 06:45:19
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answer #1
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answered by jaya 1
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Absolute value of -6 is 6
the Absolute value of 2 is -2
so.. -6 - 2
-6 + -2
= -8 final answer
2007-04-05 10:51:16
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answer #2
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answered by Anonymous
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- │- 6│- │2│
When you remove the vertical bars from the equation and a negative (-) sign is between the two bars. It means - ( - 6) = 6
- 6 - 2 = - 8
- - - - - - - - s-
2007-04-05 07:04:42
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answer #3
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answered by SAMUEL D 7
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-8
Absolute value of -6 is 6 and absolute value of 2 is 2.
So it goes -6 - 2 = -8
2007-04-05 06:46:42
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answer #4
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answered by Anonymous
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So these are absolute values.
... = - 6 - 2 = -8.
2007-04-05 06:42:10
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answer #5
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answered by Anonymous
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Vect worked out the first one for you, listed the following are the others: 12) A variable is A letter that holds the position for some unknown fee in arithmetic. 17) a+2c-5b-c+a-b = 2a+c-6b 21) W = 15s + 25m
2016-12-03 08:22:05
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answer #6
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answered by ? 3
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absolute value of -6 is 6 and absolute value of 2 is 2
so.. -6 - 2
-6 + -2
= -8
2007-04-05 06:41:13
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answer #7
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answered by Glitter 5
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Whatever is in the brackets becomes positive, so you get:
-(6) - (2) = -8
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By the way... It's the SHIFT of the key that's above ENTER and below BACKSPACE.
2007-04-05 06:43:18
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answer #8
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answered by Mathematica 7
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You can put absolute value line by pressing the shift key and the back slash at the same time.
i am sure you got the answer from some one
2007-04-05 06:49:08
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answer #9
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answered by Anonymous
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the vetical lines are used to indicate that the absolute value of number in b/w them should be used. absolute value means you disregard the "sign" [+ or -]. so:
-I-6I - I2I = -6 -2 = 8
2007-04-05 07:04:39
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answer #10
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answered by rÅvi 2
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