domain of y=2x^2?

Answer 1

All real numbers (denoted by R symbol).

Answer 2

Hi,

The domain is all real numbers because you can square any number and multiply it by 2, so you can work out y values for anything!

If you had a problem like y = 10/(x - 4) the domain would be all real numbers except 4, because if you put in 4 for x, it would make the denominator equal to zero and you can't divide 10/0 - it's undefined.

If you had y = sqrt( x - 8), the domain would be x >= 8 because you can't take the square root of a negative number so you have to make sure what is inside the radical will not be negative.

I hope that helps!! :-)

Answer 3

Every real number has a real square, and can be multiplied by 2. Thus, the domain is R.

OTOH, the range is all non-negative real numbers, because if y is non-negative, we can take x=sqrt(y)/2, but y cannot be negative, for if y<0 so is y/2 = x^2.

Answer 4

X is in Real domain

Answer 5

For which numbers are you able to calculate twice the square ?

These numbers forms the domain of your function.

Answer 6

domain is R

Answer 7

x element of R...ie all real numbers

its graph is like an upside down bowl...the graph of x^2 if you know it...just with the curves tending to infinity at a larger gradient (more quickly if you will)

Answer 8

you can put any number in that equation for x

domain (-infinity, +infiinity)

however since it is a square function, you will get back only positive values, so range would be

range= [0, +infinity)

Answer 9

The above answerer is faulty. it really is a linear function no longer a quadratic function. next time do no longer have deceptive titles. The area and decision of this linear function is all authentic numbers.

Answer 10

put different values for x:
say for eg:
x=1, y= 2
x=2, y=8
x=3, y=18...etc...

Domain of y ={1,2,3,....}
Range of y={2,8,18,....}

Answer 11

0 to infinity