2007-04-05 05:21:11 · 3 answers · asked by sjsugiant 2 in Science & Mathematics ➔ Chemistry
Write a balanced equation for the combustion, and this will tell you how many moles of water are formed for each mole of benzene. Then figure how many moles of benzene you are starting with by dividing the mass by benzene's molecular wt. Multiply this by the number of moles of water formed by one mole of benzene. You now have the moles of water formed. Multiply the moles H2O by H2O's mol. wt. and you will have the grams H2O formed
2007-04-05 05:29:52 · answer #1 · answered by theprof73 3 · 0⤊ 0⤋
You gotta write a balanced equation, like
C6H6 + 7.5O2 -> 3H2O + 6 CO2
This shows that for each MOLE of benzene burned, three MOLES of water are formed.
So, convert grams to moles (39g/78 g/mole)=0.5
From our equation, 1.5 moles of water are formed
So, convert moles to grams (1.5x18=27 g)
THIS IS IMPORTANT, so get in the practice of doing this (grams of reactant-moles of reactant - moles of product-grams of product)
2007-04-05 12:30:12 · answer #2 · answered by cattbarf 7 · 0⤊ 0⤋
3 moles of water per mole of benzene.
39/78 = 0.50 moles of benzene
3 x 0.5 = 1.5 moles water
1.5 x 18 g/mole = 27 g water
2007-04-05 12:34:31 · answer #3 · answered by Robert J 2 · 0⤊ 0⤋