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given the solution:
PbI2--->(reverse reaction)<----Pb^2+(aq)+sI^-(aq)
what is the answer to the above question?
(1)Pb(No3)2
(2) LiNO3
(3) Ca(No3)2
(4)KNO3

2007-04-05 05:10:01 · 2 answers · asked by mike 1 in Science & Mathematics Chemistry

2 answers

(1) lead nitrate

Lead Iodide is highly insoluble. The Ksp of PbI2 is 9.8 x 10^-9, so increasing the concentration of lead ions would cause further PbI2 to precipitate.

2007-04-05 05:14:46 · answer #1 · answered by Dave_Stark 7 · 0 0

lead nitrate

2007-04-05 05:22:00 · answer #2 · answered by Jewl 2 · 0 0

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