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PbI2(s)---><----- Pb^2+(aq)+OH^1-(aq)

what is the concentration of I^1- at eqilibrium if the [Pb^2+} is 0.10M?

how do i do a problem like this?

2007-04-05 04:51:34 · 1 answers · asked by mike 1 in Science & Mathematics Chemistry

1 answers

Assuming that you have written the equation wrongly, the concentration of I- ions is simply double that of the Pb2+ ions.

Maybe this was a solubility product question, in which case you need to give the information in a much clearer manner.

2007-04-06 21:12:48 · answer #1 · answered by Gervald F 7 · 0 0

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