Determination of ionization constant question~~?

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Determination of ionization constant question~~?

1g of unknown acid mix with 120mL water.
then takes 25mL of this mixture and titrate with 0.1M NaOH.

and takes 4.475mL of NaOH to reach end point.

how to find the initial concentration of weak acid?

i only know how to get the moles of NaOH. and from there i'm stucked... so please help..

2007-04-05 04:25:31 · 2 answers · asked by mr.x 1 in Science & Mathematics ➔ Chemistry

2 answers

I think you can assume that the acid and the NaOH are reacting in a 1:1 ratio. So, the moles of NaOH = moles of acid. Just divide the moles of acid by the 0.120 L, and you'll have the molarity of the acid.

2007-04-05 04:47:01 · answer #1 · answered by hcbiochem 7 · 0⤊ 0⤋

Ca.Va=CbVb a=acid & b=base
25 * Ca = 4.475*0.1 , so; Ca=0.0179M
GOOD LUCK!

2007-04-05 13:40:46 · answer #2 · answered by Master of Chemistry 2 · 0⤊ 0⤋