y = mx + b
where m is slope and y-intercept is b.
y = (-1)x + 2/5
2007-04-05 03:47:51
·
answer #1
·
answered by Mathematica 7
·
0⤊
0⤋
x-y+2/5=0
2007-04-05 04:03:30
·
answer #2
·
answered by RISHABH PAL 1
·
0⤊
0⤋
y=-x+2/5
2007-04-05 04:24:38
·
answer #3
·
answered by Neelam 2
·
0⤊
0⤋
y=-x+2/5
2007-04-05 03:50:31
·
answer #4
·
answered by bruinfan 7
·
0⤊
0⤋
y=-x+2/5
2007-04-05 03:48:06
·
answer #5
·
answered by trojanknight_96 3
·
0⤊
0⤋
the form of the slope-intercept equation is y = mx + b the place m is the slope (exchange in y / exchange in x) and b is the y-intercept from the graph, 2 factors are (0,-3) and (one million.5,0) so, the exchange in y is 3 and the exchange in x is one million.5 so, the slope is the ratio: 3/one million.5 = 2 = m the line intercepts the y axis at -3 = b so, the slope-intercept equation is y = 2x - 3
2016-11-07 07:04:06
·
answer #6
·
answered by ? 4
·
0⤊
0⤋
slope-intercept equation => y=mx +c
c= y intercept = 2/5
m = slope = -1
so
=> y = (-1)x + (2/5)
=> y = -x + (2/5)
multiply 5 throughout the equation
=> 5y = -5x + 2
or
=> 5y +5x = 2
2007-04-05 04:42:52
·
answer #7
·
answered by CURIOUS SID_B 2
·
0⤊
0⤋
using the equation y = mx + b you can sub in and get:
y = -1x + 2/5
2007-04-05 05:12:13
·
answer #8
·
answered by Anonymous
·
0⤊
0⤋
5x+5y-2=0 or 5y=-5x+2 as u want to write it
2007-04-05 03:48:59
·
answer #9
·
answered by solver 3
·
0⤊
0⤋
(y-y1)=m(x-x1)
(x1,y1) is (0,2/5) and m = -1
(y-2/5)= -(x)
x+y=2/5
5x+5y=2
2007-04-05 03:48:40
·
answer #10
·
answered by Rajkiran 3
·
0⤊
0⤋