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if its 1.8 high, 6m long and has a 20deg pitch? How high in middle?

2007-04-05 03:14:50 · 3 answers · asked by mailric 1 in Science & Mathematics Mathematics

TY so far guys - I want it 1.8 meters high at the lowest point of the roof (i.e. the bottom of the pitch). Its 5 meters wide and 6 meters long. I want the pitch front to back (over the 6 meter length). If I have 20 degree pitch then how high will the roof become in the middle (i.e. at the top of the pitch. My trigonometry is useless!

2007-04-05 03:36:23 · update #1

3 answers

I'm a little confused by your terminology...

is the 1.8 the length of one side of the roof? (From the top of the wall to the peak?)

If that's the case, then the height of the peak is x...

sin 20 = x/1.8
x = (1.8)(sin 20) = 0.6156 units.

(If the 1.8 was meters, than the peak is 0.6156 meters. You didn't give a unit of measurement for the 1.8 in your question.)

2007-04-05 03:26:50 · answer #1 · answered by Mathematica 7 · 0 0

tan 20° = rise / run = height at center / ½ length of the garage
tan 20° ≈ 0.0364 ≈ height at center / 3 m
3 (0.364) m ≈ height at center
1.092 m ≈ height at center or middle

That's 1.092 meters from the bottom of the pitch. To find out how high off the ground that will be, just add 1.092 to 1.8 meters. That's approximately 2.892 meters or about 9.488 feet off the ground.

2007-04-05 04:28:04 · answer #2 · answered by MathBioMajor 7 · 0 0

tan 20 = 0.364

the central height will be 1.8 + halfwidth * 0.364
but you havent said how wide it will be

ok .. so its 5 metres wide so ...
1.8 + 2.5 * 0.364 = 2.71
if you have the peak running from front to back

or 1.8 + 3 * 0.364 =2.89 if you really are going to have the crest going sideways across the middle ... I'd have thought that would look very odd.

2007-04-05 03:26:45 · answer #3 · answered by hustolemyname 6 · 0 0

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