You didn't give enough information to figure it out...
There are a lot of solutions...
36+36+36
1+2+105
10+20+78
to name a few....
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7194 - x = x(0.10)(1)
7194 - x = 0.10x
7194 = 1.10x
$6540 = x
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First angle = x
Second angle = 4x
Third angle = (x + 4x) - 45
All three sum to 180, so:
180 = x + 4x + (x + 4x) - 45
180 = 10x - 45
225 = 10x
22.5 = x
First angle = 22.5
Second = 4(22.5) = 90
Third = (90 + 22.5) - 45 = 67.5
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First score = 67
Second score = x - 7
Third score = x
[67 + (x - 7) + x] / 3 = 84
(60 + 2x) / 3 = 84
60 + 2x = 252
2x = 192
x = 96
Second score = 96 - 7 = 89
Third score = 96
2007-04-05 03:05:30
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answer #1
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answered by Mathematica 7
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You cannot find three ages from just the sum. You need more information, such as the fact that all three ages are equal. If that is the case, then the ages are each 108/3 = 36.
If s is the sum borrowed, then 1.10s = $7194.
s = $7194 / 1.10 = $6540.
Let the first angle be f. Then the second angle is 4f, and the third is 4f + f - 45 = 5f - 45 deg..
The sum of all the angles is 180deg.
Therefore f + 4f + 5f - 45 = 180
10f - 45 = 180
10f = 225
f = 22.5 deg.
The angles are therefore 22.5deg, 90deg, 67.5deg.
Let the third score be t. Then the seond was t - 7.
The total score was 3 * 84 = 252.
252 = 67 + 2t - 7 = 60 + 2t
192 = 2t
t = 96
Therefore the third score was 96, and the 2nd score was
t - 7 = 89.
2007-04-05 03:11:28
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answer #2
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answered by Anonymous
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1. can be anything 1,1,106 or 50, 40, 18; for a uniqe answer some information is missing
2. suppose borrowed x. after 1 yr he has to return 1.1x
so, 1.1x=7194, so x=$6540
3. suppose 1st angle = x
so, 2nd angle=4x
so, 3rd angle=x+4x-45
total=10x-45 which should be 180
10x-45=180
x=22.5
so, angles are 22.5, 90, 67.5
4. average=84 on 3 exams
so, total=84*3=252
suppose third score=x
so, 2nd score=x-7
1st score=67
total=2x+60
2x+60=252
x=192/2=96
so, 2nd exam score=89
third exam score=96
2007-04-05 03:09:32
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answer #3
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answered by solver 3
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for the first one it is x+x+1+x+2=108, solve for x. X will equal 35.then 35+36+37=108
2007-04-05 03:03:41
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answer #4
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answered by Jon S 2
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;et
x = the age of first person
x + 1 = the age of thesecond person
x + 2 = the age of the third person
108 = the sum of the ages
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x + x + 1 + x + 2 = 108
3x + 3 = 108
3x + 3 - 3 = 108- 3
3x = 105
3x / 3 = 105 / 3
x = 105/3
x = 35
The age of the first person 35
The age of the second person 36
The age of the third person 37
- - - - - - -s-
2007-04-05 04:06:20
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answer #5
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answered by SAMUEL D 7
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2016-12-03 08:07:44
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answer #6
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answered by Anonymous
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(1) 36, 36, 36
That's all I can give now, got to go
2007-04-05 03:09:27
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answer #7
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answered by Anonymous
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