BF3 is an electron deficient molecule. B has only 5 electrons. BF3 has a tendency to react with NH3 to form a BF3NH3.
Suggest reason(s) for the reaction and describe the bonding of BF3NH3.
I will be very generous to vote for your answer which is the most elaborated and precise as your best answer.
2007-04-05 02:45:23 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
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it is possible they belong to group 1 that react with group7.
2007-04-05 02:49:12 · answer #1 · answered by Anonymous · 0⤊ 1⤋
The reaction between these two is a Lewis Acid-Lewis Base reaction where NH3 (acting as a Lewis base) shares its pair of nonbonding electrons to boron (which is a Lewis acid). The electrons fill the last orbital of the valence shell of boron and boron then attains a tetrahedral geometry and a completed shell.
2007-04-05 09:56:26 · answer #2 · answered by hcbiochem 7 · 0⤊ 0⤋
Actually this is an Lewis acid base reaction,but let me xplian it simple.
In BF3 B in excited state has confi. 1s2 2s1 2p2.So these 2s & 2p orbitals hybridise to form 3sp2 hybrid orbital.these three are bonded to 3 Fluorines resp. But in the valence shell B has 6electrons only.It therefore take 1bond pair from NH3 to get octet state.
This type of bonding is called CO-ORDINATE COVALENT BOND or DATIVE BOND .
2007-04-05 10:16:52 · answer #3 · answered by vanajatha_sudeep 1 · 1⤊ 0⤋
Boron in BH3 is electron deficient which will attract lone pair fron the nitrogen in NH3 to form dative covalent bonding.
2007-04-05 09:53:54 · answer #4 · answered by lijia 1 · 0⤊ 0⤋