y+6=-1/3x and passes through the point (-4,-5)
2007-04-04 19:19:16 · 4 answers · asked by Case 1 in Science & Mathematics ➔ Mathematics
you have y = (-1/3)x - 6. all lines perpendicular have slope = 3, so plug in (-4,-5) to y = 3x + b to find b.
-5 = 3(-4) + b
7 = b
y = 3x + 7.
2007-04-04 19:26:34 · answer #1 · answered by Philo 7 · 0⤊ 0⤋
First, the slope of the line perpendicular to y+6=-1/3x will have slope = -1/m
Hence, slope = -1/(-1/3) = 3
For linear equation, y = mx + c. m we found to be 3.
So, your equation now is y = 3x + c
This equation passes through (-4,-5). Substitute this point into the equation, we have
-5 = 3(-4) + c
c = -5 +12 = +7
So, the line is y = 3x + 7
2007-04-04 19:29:22 · answer #2 · answered by looikk 4 · 0⤊ 0⤋
y = 3(x + 4) - 5
2007-04-04 19:28:52 · answer #3 · answered by Helmut 7 · 0⤊ 0⤋
you recognize the slope must be the adverse reciprocal of -a million/3 it is +3 and y=5 while x= -4 so 5=3(-4) + b so b=17 and y=3x+17 yet that decision isn't there. except decision b is mistyped
2016-11-26 03:35:26 · answer #4 · answered by donges 4 · 0⤊ 0⤋