A painter determines there may be delays on finishing a job due to rain or a shortage of workers. He predicts there is a 15% chance of rain and a 12% chance of a shortage of workers. What is the probability that none of these events will occur?
2007-04-04 18:41:53 · 5 answers · asked by dixie k 1 in Science & Mathematics ➔ Mathematics
The probability that it won't rain is
P(no rain) = 1 - P(rain)
The probability that there won't be a shortage of workers is
P(no shortage of workers) = 1 - (shortage of workers)
The probability that neither of two (independent) events will occur is
P(no rain AND no shortage of workers)
= P(no rain) x P(no shortage)
You get the calculator and plug and chug.
2007-04-04 18:47:26 · answer #1 · answered by Paul O 2 · 0⤊ 0⤋
Assuming that the probability of rain and the shortage of workers are independent, the probability of having no rain and enough workers would just be (.85)(.88)
2007-04-04 18:46:13 · answer #2 · answered by Mr T 2 · 0⤊ 0⤋
prob. of rain=15%=0.15
prob. of shortage=12%=0.12
total=.15+.12=0.27
prob.of none of these cases=1.0-0.27=0.73
or
% case of rain=15%
%case of shortage=12%
%of none of these cases=73%
prob on none=0.73
2007-04-04 19:28:08 · answer #3 · answered by Anonymous · 0⤊ 0⤋
1-15/100-12/100+(15*12)/10000
2007-04-04 18:44:32 · answer #4 · answered by Making_Happy 4 · 0⤊ 0⤋
If the events are mutually exclusive,
P = 1 - 0.15 - 0.12 = 0.73
If they are not mutually exclusive,
0.73 < P ⤠0.85
2007-04-04 18:49:44 · answer #5 · answered by Helmut 7 · 0⤊ 0⤋