The probability that event A occurs is .79. The probability that event B occurs is .58. The probability that both events A and B occur is .26, find P(B\A).
2007-04-04 18:33:46 · 3 answers · asked by Susie L 1 in Science & Mathematics ➔ Mathematics
P(B\A) = P(B |~| A) / P(A) = 26/79
B |~| A = B intersection A
2007-04-04 18:42:05 · answer #1 · answered by Nishit V 3 · 0⤊ 0⤋
This is conditional probability.
P(B | A) = P(A â© B) / P(A) = .26 / .79 = 26/79 â 0.3291139
2007-04-05 02:31:24 · answer #2 · answered by Northstar 7 · 0⤊ 0⤋
If I remember the notation correctly, P(B\A) represents the probability that B happens given that A has already happened.
And if I remember the theory correctly,
P(B\A) = P(A and B) / P(A)
In this case, that would mean P(B\A) = .26 / .79. I'll let you get the calculator.
That's assuming I remember probability theory correctly...
2007-04-05 01:41:22 · answer #3 · answered by Paul O 2 · 0⤊ 0⤋