a block that weighs0.5n is being pushed?

Question

with a force of 1.0n to the right what is the net force acting on the block?

Answer 1

Not enough info.

But we can write some relationships; then you have to provide the numbers.

Assuming there is friction, the net forces are f = ma = P - kN; where P = 1.0 Newtons = the pushing force. m = W/g = the mass of the block with W = .5 Newton and g = 9.81 m/sec^2. at Earth's surface.

k = the sliding friction coefficient (which you have not supplied) and N = W cos(theta) = .5 Newton; where theta = 0 = the slope angle of the plank the block is sliding over. So the net force f = P - kN = 1.0 - k(.5); you need the k. You can do the math if you know k; otherwise, it can't be worked.