English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

2007-04-04 17:44:28 · 7 answers · asked by sakon m 1 in Science & Mathematics Mathematics

7 answers

because you are first taking the natural log of x and then raising it to the 1/2 power instead of raising x to the 1/2 power and then taking the log.

2007-04-04 17:49:52 · answer #1 · answered by rybread9 1 · 2 0

Raising the figure to the 1/2 power is not the same as 1/2 times the figure.

Example:
3^2 = 9 (3 to the second power, or squared)
3 X 2 = 6

Not equal.

2007-04-04 17:59:44 · answer #2 · answered by Stratman 4 · 0 0

The log identity in question goes

log[base b](a^c) = c log[base b](a)

In this case, all of [ln(x)] is to the power of 1/2 (because of the brackets).

2007-04-04 17:59:14 · answer #3 · answered by Puggy 7 · 0 0

the rule is: ln (x^n) = n ln(x).
therefore, the correct equation is ln(x^[1/2]) = [1/2] ln(x).

2007-04-04 17:56:15 · answer #4 · answered by hitherto.24 1 · 0 0

for the left hand side you are finding the square root of ln(x) but for the right hand side you are find the ln of square root (x)

asumming x is 100

root of ln100 is not the same as ln10

2007-04-04 17:50:31 · answer #5 · answered by ong_joce 2 · 0 1

Because ln(x^.5)=.5ln(x) not the way you have it.

2007-04-04 17:50:19 · answer #6 · answered by bruinfan 7 · 0 1

shfg

2007-04-08 08:34:24 · answer #7 · answered by Alexii L 1 · 0 0

fedest.com, questions and answers