because you are first taking the natural log of x and then raising it to the 1/2 power instead of raising x to the 1/2 power and then taking the log.
2007-04-04 17:49:52
·
answer #1
·
answered by rybread9 1
·
2⤊
0⤋
Raising the figure to the 1/2 power is not the same as 1/2 times the figure.
Example:
3^2 = 9 (3 to the second power, or squared)
3 X 2 = 6
Not equal.
2007-04-04 17:59:44
·
answer #2
·
answered by Stratman 4
·
0⤊
0⤋
The log identity in question goes
log[base b](a^c) = c log[base b](a)
In this case, all of [ln(x)] is to the power of 1/2 (because of the brackets).
2007-04-04 17:59:14
·
answer #3
·
answered by Puggy 7
·
0⤊
0⤋
the rule is: ln (x^n) = n ln(x).
therefore, the correct equation is ln(x^[1/2]) = [1/2] ln(x).
2007-04-04 17:56:15
·
answer #4
·
answered by hitherto.24 1
·
0⤊
0⤋
for the left hand side you are finding the square root of ln(x) but for the right hand side you are find the ln of square root (x)
asumming x is 100
root of ln100 is not the same as ln10
2007-04-04 17:50:31
·
answer #5
·
answered by ong_joce 2
·
0⤊
1⤋
Because ln(x^.5)=.5ln(x) not the way you have it.
2007-04-04 17:50:19
·
answer #6
·
answered by bruinfan 7
·
0⤊
1⤋
shfg
2007-04-08 08:34:24
·
answer #7
·
answered by Alexii L 1
·
0⤊
0⤋