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10 answers

-15 and +2

2007-04-04 17:39:37 · answer #1 · answered by craigcougar64 2 · 0 0

alright, for this, you have to create some variables. Let X and Y be the 2 numbers.

so you know that X*Y = -30 and X+Y = 13.

rearrange the first equation by dividing both sides by X, so you get Y = -30/X

Put this value of Y into the second equation:
X + (-30/X) = 13,

multiply both sides by X to get rid of the fraction:
X^2 - 30 = 13X..........bring everything to the left
X^2 - 13X - 30 = 0..........solve the quadratic equation

you could either look for 2 numbers that add to -13 and multiply to -30 (but that is what the question asks for, so if you could do that, then you wouldn't need to do this. so use the quadratic equation:

X = [13 +- sqrt (13^2 - 4(1)(-30))] / 2
X = [ 13 +- sqrt 289] / 2
X = (13 +- 17) / 2
X = 30/2 and -4/2
X = 15 and -2

once you have this value of X, put it into any of the 2 equations you have above:

X*Y = -30
(15) * Y = -30
Y = -30/15 = -2

X*Y = -30
(-2) * Y = -30
Y = -30/-2 = 15

X + Y = 13
(15) + Y = 13
Y = -2

-2 + Y = 13
Y = 15




So you get the same values no matter which X you use in the equations. So the 2 numbers are 15 and -2.

Hope that helped you

2007-04-05 00:45:02 · answer #2 · answered by Anonymous · 1 0

-2 and 15

2007-04-05 01:11:40 · answer #3 · answered by Dave aka Spider Monkey 7 · 0 0

-15 & +2

2007-04-05 00:48:30 · answer #4 · answered by Christian Mata 2 · 0 0

15, -2

2007-04-05 00:39:40 · answer #5 · answered by jholcomb 3 · 0 0

first set up two equations representing the two unknowns.
It should look something like this:

(x)(y)= -30
x+y =13
here x and y repressent the two unknown #'s.
next solve both equations for y (or x):
-30x^-1=y
-x+13=y
next solve simultaneously to get two sets of solutions:
(or plug equation 1 into equation 2 or vice versa)--and solve
first soln:
x= -2 and y=15
or
x= 15 and y= -2
If you have a TI-83 plug both equations into the calculator (the ones set equal to y) then sove graphically by finding the intersection of the two curves. hope this helps....

2007-04-05 01:09:53 · answer #6 · answered by rominger 1 · 0 0

15 and -2 because:

15*-2= -30
15+-2=13

2007-04-05 00:48:43 · answer #7 · answered by sunshineangel 3 · 0 0

it's either -15 and +2 or +15 and -2. could go either way

2007-04-05 00:43:46 · answer #8 · answered by cmeilinli 3 · 0 0

15 and -2
to solve these, list the factors of the big number. Then play with them and the negative signs.

2007-04-05 00:39:54 · answer #9 · answered by msmthtchr 3 · 0 0

Or you can turn them into equations
xy=-30
x+y=13

2007-04-05 00:42:33 · answer #10 · answered by Stina B 3 · 0 0

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