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) Find the slope of any line perpendicular to the line through points (0, 5)
and (-3, -4).

2007-04-04 17:08:11 · 5 answers · asked by Sweetie 2 in Science & Mathematics Mathematics

5 answers

The 2 pts provide a line with slope +3, so your perpendicular line must have a slope -1/3. [Except for horizontal and vertical lines, perpendicular lines have slopes that are the negative reciprocal of each other.]
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slope m = [y1 - y2] / [x1 - x2] which in your case becomes

m = [5- (-4)] / [0 - (-3)] = 9/3 = 3 OR

m = [ - 4 - 5] / [- 3 - 0] = - 9/ (- 3) which also = 3. etc.

2007-04-04 17:15:42 · answer #1 · answered by answerING 6 · 0 0

Since we dont have to find a specific perpendicular line, we only have to find the slope of the line through the 2 points. Thats given by
[ 5 - (-4) ]/ [ 0 - (-3) ]= 3. The perpendicular line is then - (1/3). Get this routine down, it's important.

2007-04-05 00:18:09 · answer #2 · answered by cattbarf 7 · 0 0

First, let us find the eqn of the line to which we want to find the perpendicular slope:
y(x) = mx + b
y(0) = m(0) + b = 5
y(-3) = m(-3) + b = -4
b = 5
-3m + 5 = -4
-3m = -9
m = 3
y(x) = 3x+5
Now lines are perpendicular if and only if the slopes have the following relationship: m2 = -1/m1
so in this case the wanted slope is m' = -1/3

2007-04-05 00:20:17 · answer #3 · answered by kellenraid 6 · 0 0

here's a visual way to help you out until you get the hang of the formulas.

Draw out the graph , 1 point is 0,5 and the other is -3, -4.
Now draw a perpendicular line through that. try (0, -5) and (-3, 4), but I might be wrong with these 2 points as I'm doing this off my head.
Then count the rise (up and down) and the run (left and right) between the 2 made up points of the perpendicular line.
Slope = Rise divided by run.

I'm currently missing my graphic calculator, otherwise I'd double check to make sure I'm 100% correct.

2007-04-05 00:19:56 · answer #4 · answered by Unseeingeye 2 · 0 0

Calculate the slope of this line. Let's say your answer is m.
Then the slope of any line perpendicular to this line with be
-1/m

2007-04-05 00:16:38 · answer #5 · answered by Scott H 3 · 0 0

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