a plane leaves the airport A and travels 580 miles to airport B at a bearing of N15 degrees E. The plane later leaves airport B and travels 400 miles to airport C at a bearing of N74degrees E. Find the distance from airport A to airport C.
2007-04-04 16:45:49 · 3 answers · asked by briteyez_pp 1 in Education & Reference ➔ Homework Help
By drawing a diagram, in the shape of a triangle with A, B and C, and the respective differences we can solve this problem. Using the straight line theorem(that two angles on opposite sides of a straight line add up to 180, we can figure out that part of angle B is 106. To find the other part, we use Z pattern on the two parallel lines heading north so we get another 15. So we know angle B is 121. Now we can use cosine law. I got 857.5 miles.
2007-04-04 16:58:09 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Can't help too much, but if you have the equation of calculating the area of a triangle, I think you can get it. One base is 580 and the other is 400, calculate the hypotenuse, (I think) - sorry.
2007-04-04 16:51:00 · answer #2 · answered by K B 3 · 0⤊ 0⤋
y = 580cos(15) + 400cos(47)
x = 580sin(15) + 400sin(47)
d = sqrt(x^2 + y^2)
BAC = arctan(x/y)
2007-04-04 16:59:10 · answer #3 · answered by Helmut 7 · 0⤊ 0⤋