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calculate the surface area of a sila whose radius is 12 ft and whose height is 42 feet.

ANND

How much grain would the silo in the previous problem hold?

2007-04-04 16:03:12 · 3 answers · asked by volley_ballchick815 1 in Science & Mathematics Mathematics

3 answers

Area = circumference (pi x D) of the base x height

Volume = area of base (pi x r^2) x height.

HTH

Charles

2007-04-04 16:09:21 · answer #1 · answered by Charles 6 · 0 0

Surface area is the "rectangular" vertical surface and one circular top. The silo sits on the ground, so you wouldn't count that circle.

Rectangle = base times height when the base is the circumference of the circle.
Rectangle = 2*pi*12*42 = 3166.73
Circle = 12^2 times pi = 452.39
Add these together for total surface area. Unit is square feet.

Volume of the silo = area of base times height
Volume = 452.39 * 42 = __________ cubic feet

2007-04-04 23:13:51 · answer #2 · answered by ecolink 7 · 0 0

area of the base = pi r^2 = pi(6^2)= 36 pi
area of the side= h*circumference of circle
= 42(pi*12) = 504 pi
total surface area = 2(area base)+ area side
= 72 pi + 504 pi
= 576pi square ft

volume = (area of base)(height)
= 36pi(42) = 1512pi ft^3 = amount of grain

2007-04-04 23:12:30 · answer #3 · answered by jaybee 4 · 0 0

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