Describe the steps for finding a line which is perpendicular to x = -3 and passes through the point (-1,4)?

Question

I need to include an explanation in my answer

Answer 1

you lost me at x= -3

so this is what I got.

y = mx + b

(-1, 4)

4 = (-3)(-1) +b
4 = 4 + b

subtract 4 from the right to left.
Example:

4 = 4 + b
-4....-4
----------------
0 = b

Answer 2

the line x = -3 is just a vertical line that that passes through x = -3 and is parallel to the y axis. perpendicular to that would be a line parallel to the x axis, which has the form y = a, where a is a constant.
since you want it to pass through the point (-1,4) the line would be y = 4. this line will hit every x value, including -1, but the only y-value it will reach is 4

Answer 3

Try to visualize these steps or sketch a coordinate graph.

Picture (draw) a vertical line passing thru (-3, 0)

Find the point (-1,4) This will be to the right of the vertical line.

Picture(draw) a horizontal line (vertical and horizontal lines should be perpendicular :) ) thru that point. This should go through 4 on the y-axis.

Answer 4

If a line has a slope of m, a perpendicular line to it has a slope of -(1/m). Here, the slope of the line x=-3 is undefined (straight up and down), so the slope of a perpendicular line is ZERO (horizontal).
However, since we specify that it passes through a point with a y value of 4, the equation will be
y = 4

Answer 5

y = -1,4
The line y = - 1,4 will be parallel to y Axe always. So it will be perpendicular to any line x = n
It will pass through all values from y and trough x = -1,4

Answer 6

well x=-3 is a straight vertical line, so your perpendicular will have to be y=somthing
and this somthing will have to pass by y=4
so the equation has to be y=4

Answer 7

oh whoops sry...i did it wrong...^^^ is right