1. How much contac paper would be needed (without overlap) to cover a rectangular box 30 inches long, 14 inches tall, and 23 inches wide. AND Find the volume of the rectangular box in the problem.
2007-04-04 15:48:58 · 5 answers · asked by volley_ballchick815 1 in Science & Mathematics ➔ Mathematics
surface area of a box is 2*L*W + 2*L*H + 2*H*W
= 2(14*23 + 30*14 + 30*23)
volume is 30*14*23
2007-04-04 15:54:15 · answer #1 · answered by metalluka 3 · 0⤊ 0⤋
you ought to understand what y and x are. then you ought to placed huge kind on a million facet and letter on the different alongside with. x-2y=6 at the same time as x=2 2-2y=6 2 cancle one yet another and go away y=6 no longer certain if i did that proper reason i dont have a pen and paper yet i'm between the best in my math class=)
2016-12-03 07:37:22 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Volume = length x height x width
Paper requirement (assuming a lid) is the sum of
2 lengh x height (2 sides)
2 width x height (2 sides)
2 width x length (top and bottom)
2007-04-04 15:55:18 · answer #3 · answered by cattbarf 7 · 0⤊ 0⤋
total surface is 2ab + 2ac + 2bc so
2x30x14 + 2x30x23 + 2x14x23 = whatever inches squared of paper
volume is 14*23*30 inches cubed
2007-04-04 15:55:39 · answer #4 · answered by w1ckeds1ck312121 3 · 0⤊ 0⤋
You would need 2,864 inches^2 to cover the box
The volume is 9660 inches^3
2007-04-04 15:54:43 · answer #5 · answered by Anonymous · 0⤊ 0⤋