a) The molar solubility of MgF2 at 25°C is 1.2E-3 mol/L. Calculate Ksp for this salt.
(b) If 0.049 mol of the slightly soluble salt C2A(s) (where "C" is the cation, "A" is the anion) dissolves in one liter of solution, calculate the solubility-product-constant for this salt.
(c) Using the appropriate Ksp value, calculate how many grams of AgCl will dissolve in one liter of water.
??? g/L
2007-04-04 15:36:49 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
The dissolution of MgF2 is to Mg+2 + 2 F-
So in saturated MgF2 solution is 1.2x10-3 g-ions of Mg and 2.4x10-3 g-ions of F
Then Ksp = 1.2x10-3 x (2.4x10-3)^2
B is pretty much the same deal
C. Since AgCl dissolves to Ag+ and Cl-,
sqrt (Ksp)= moles of AgCl that dissolve/liter
Multiply by mol weight to get grams
2007-04-04 15:52:41 · answer #1 · answered by cattbarf 7 · 0⤊ 0⤋
The GMW of hydogen is a million so as which skill there is 29 g of Cl interior the given quantity of HCl. you notice that a million/2 of the Cl is used in MnCl2 so, as a result, a million/2 of the Cl is interior the gas Cl2. Your answer is d) 14.6g.
2016-12-15 16:27:35 · answer #2 · answered by ? 4 · 0⤊ 0⤋