XH2O is heated. If 243.4400gms of hydrate releases 108.1201gms of water, what is the value of X in the hydrate formula. Molecular weight of the anhydrous compound is 405.97 g/mol
2007-04-04 15:31:04 · 2 answers · asked by sjsugiant 2 in Science & Mathematics ➔ Chemistry
Weight of anhydrous compound = 243.4400-108.1201 = 135.3199 g
135.3199g / 405.97 g/mole = 0.333 moles
108.1201g H2O / 18.0152 g/mole = 6.00 moles
6.00 moles H2O / 0.333 moles anh. cpd = 18
Co2(SO4)3 . 18 H2O
2007-04-04 15:39:02 · answer #1 · answered by TheOnlyBeldin 7 · 0⤊ 0⤋
Your problem should be restated as
Co2(SO4)3. x H2O as the initial compound.
Let A be the initial amount of hydrate.
Then A-108.12 = initial weight of anhydrate
Divide (A-108.12)/405.97, this tells you the initial number of MOLES of the hydrate. Call this fh
Now, if fh moles of hydrate release 6 moles of water, 6/fh tells you what x is.
2007-04-04 15:41:29 · answer #2 · answered by cattbarf 7 · 0⤊ 0⤋