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I am working on applications of rational expressions and comples fractions. I have no clue how to set this problem up to solve it. Can you help?
A plane flies 720 mi against a steady 30-mi/h headwind and then returns to the same point with the wind. If the entire trip takes 10 h, what is the plane's speed in still air?

2007-04-04 15:10:33 · 3 answers · asked by feona_1999 1 in Science & Mathematics Mathematics

3 answers

distance=rate * time
Therefore, 720/(x-30)+720/(x+30)=10
Solve this problem and you will have your solution.

2007-04-04 15:15:23 · answer #1 · answered by bruinfan 7 · 1 0

ok so the 720mi / (x+30mi/h) = time to there
720mi / (x-30mi/h) = return time
720 / (x+30) + 720 / (x-30) = 10hours
720(x-30) + 720(x+30) = 10(x+30)(x-30)
720x - 21600 + 720x + 21600 = 10x^2 - 9000
x^2 - 144 - 900=0
(144 +- sqrt(17136)) / 2
find those two solutions and the positive one is the planes speed in still air, so x = speed with no wind, sry got no calculator on me.

2007-04-04 15:19:09 · answer #2 · answered by w1ckeds1ck312121 3 · 0 0

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2016-12-15 16:24:45 · answer #3 · answered by ? 4 · 0 0

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