1. To divide 7 / x +2 by x - 2 / 14 you can multiply by ?
2.simplify 9k - 4 + 2k
3. find the product: (6y + 5)(2y +3)
thanks everyone
2007-04-04 14:33:01 · 6 answers · asked by Tessy 1 in Science & Mathematics ➔ Mathematics
1)7/(x+2)/(x-2)/14
7/(x+2)*14/(x-2)=
98/(x+2)(x-2)
2)9k-4+2k
11k-4
3)(6y+5)(2y+3)
12y^2+18y+10y+15
12y^2+28y+15
I hope this helps!
2007-04-04 15:12:48 · answer #1 · answered by Anonymous · 4⤊ 0⤋
1. As for normal fractions, you tip the second one upside down and multiply; so here you multiply by 14 / (x-2)
7/(x+2) ÷ (x-2)/14
= 7/(x+2) × 14/(x-2)
= (7×14) / ((x+2)(x-2))
= 98 / (x^2 - 4).
2. 9k - 4 + 2k
= (9k + 2k) - 4
= (9 + 2)k - 4
= 11k - 4.
3. (6y+5) (2y+3)
= 6y(2y) + 6y(3) + 5(2y) + 5(3)
= 12y^2 + 18y + 10y + 8
= 12y^2 + 28y + 8.
2007-04-04 14:40:17 · answer #2 · answered by Scarlet Manuka 7 · 1⤊ 0⤋
1.) [7/(x+2)] / [(x-2)/14] --> get the reciprocal of the denominator and multiply
[7/(x+2)] * [14/(x-2)] = 98/[(x+2)(x-2)] or 98/(x^2-4)
2.) 9k - 4 + 2k = 11k -4
3.) (6y + 5) (2y + 3) --> multiply by FOIL
12y^2 + 28y + 15
2007-04-04 14:43:20 · answer #3 · answered by jeffdeg 2 · 1⤊ 0⤋
1. you can multiply by 14 / x -2
2. 9k - 4 + 2k
9k + 2k - 4
11k - 4
3 i don't know how to do no 3
2007-04-05 13:43:46 · answer #4 · answered by Anonymous · 0⤊ 0⤋
1. reciprocal
2.11k-4
3. multiply the problem out and you get 12y^2+18y+10y+15, simplify and you get 12y^2+28y+15
2007-04-04 14:38:00 · answer #5 · answered by ? 2 · 0⤊ 0⤋
1. x-2/2(x+2)
2. 7k-4
3. foil 12y^2+18y+10y+15
12y^2+28y+5
2007-04-04 14:42:29 · answer #6 · answered by Justina 3 · 0⤊ 0⤋