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Two long parallel wires 6.00 cm apart carry 15.5 A currents in the same direction. Determine the magnetic field strength at a point 12.0 cm from one wire and 13.4 cm from the other.

I don't understand what to do. I saw another one like this question but I'm still confused.. please help ^_^

2007-04-04 11:28:16 · 2 answers · asked by Anonymous in Science & Mathematics Physics

Two long parallel wires 6.00 cm apart carry 15.5 A currents in the same direction. Determine the magnetic field strength at a point 12.0 cm from one wire and 13.4 cm from the other.

Ok I mean.. I know how this problem works but I don't know how to use it as components.. and how to use the angles once I find it..

2007-04-04 14:03:22 · update #1

2 answers

The three distances determine a triangle so you can find the coordinates of the point in the x y plane perpendicular to the wires.
Find the vector Field from each wire individually. If you don't know how see http://hyperphysics.phy-astr.gsu.edu/hbase/magnetic/magcur.html
The resultant field is the vector sum, that is add x components and then y components and the strength is the magnitude of the vector


The field vector is perpendicular to the vector from the wire to the point. so put the wires on the x axis, then if vector to the point makes an angle a with the x axis the Field vector will make a angle ( 90-a) with the x axis so the x component will be Cos(90-a) and the y component will be Sin(90-a). Draw a picture and keep your signs correct.

2007-04-04 13:28:24 · answer #1 · answered by meg 7 · 0 0

SO YOU HAVE TWO POINTS ON PAPER HAVING DISTANCE 2d. megnetic field zero will be on the mid point of this line. (there will be many points where the megnetic field will be zero but THERE IS ONLY ONE POINT ON PAPER)

2016-03-28 23:37:18 · answer #2 · answered by ? 3 · 0 0

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