its extra credit so i'm not trying to cheat I just need to get my grade up!!(majorly)
2007-04-04 10:49:58 · 3 answers · asked by Jordyn N 2 in Science & Mathematics ➔ Chemistry
Always happy to help students, regardless. :D Atomic weight: Al = 27
25.0gAl x 1g-atomAl/27gAl x 6.02x10^23atomsAl/1g-atomAl = 5.57x10^23atomsAl
2007-04-04 10:56:59 · answer #1 · answered by steve_geo1 7 · 1⤊ 0⤋
divide 25 to the atomic mass of aluminium and multiply the result with avagadros number, that will give the number of atoms
2007-04-04 17:58:48 · answer #2 · answered by abcdef 2 · 0⤊ 0⤋
to find the number of moles use the equation:
n=m/MW
=25.0 g/ 27 g/mol
= 0.93 mols
to find # of atoms :
# of atoms= number of mole * Avagadro's #
=0.93 mols * (6.022 *10^23)
=5.6 * 10 ^23 atoms of Al
2007-04-04 17:59:12 · answer #3 · answered by xxbabiesue123xx 2 · 0⤊ 0⤋