2007-04-04 08:43:59 · 6 answers · asked by Keshia M 1 in Science & Mathematics ➔ Chemistry
IF you had the anhydrous form it would be very difficult to dissolve but not impossible.
CaCl2(anhydrous) MW= 110.99 g/mole
but you want 3 liters of this so
xmoles/3liter = 2moles/liter ==> x = 6 moles = 666 g
take 666 g CaCl2(anhydrous) in 3 liters
and you will have a 2 M solution
2007-04-04 08:55:09 · answer #1 · answered by Dr Dave P 7 · 0⤊ 0⤋
I have no idea how much you know about Chemistry, so I'm gonna go over the whole thing.
First off- you have to add 666g of CaCl2. Here's why:
Molarity is a ratio of moles in litres- a 1 M solution would have a ratio of 1 mole for every litre. So, your 2 molar (or 2 M) solution should have 6 moles of CaCl2 (twice as much as the 3 litres).
Do you know what moles are? I'm not gonna bother explaining everything if you don't- just look it up on google or wikipedia. but to find the amount of grams of CaCl2 in 1 mole of CaCl2, calculate its atomic mass. Ca has a mass of 40, Cl had a mass of 35.5.
40+35.5+35.5= 111
so 1 mole of CaCl2 has 111g in it. We need 6 moles, so 111 * 6 =666g, and that's your answer.
You would put 666g into a beaker, and then fill it with water up to the 3 L mark.
2007-04-04 08:55:52 · answer #2 · answered by chpsalumni 2 · 0⤊ 0⤋
Mass molar Ca Cl2 = 40+2*35.5 = 40+71 =11
a 2 molar solution contains 111*2 =222g /L of CaCl2
so 3 liter use 3*222=666g of CaCl2
2007-04-04 08:48:36 · answer #3 · answered by maussy 7 · 0⤊ 0⤋
You need 6 moles of Ca for that sol'n.
6 * 40g/mol = 240g = 2 * 10^2g
(You only have one significant figure.)
2007-04-04 08:50:28 · answer #4 · answered by Anonymous · 0⤊ 0⤋
6 moles or 6*(40+71) = 6,66 grams.
2007-04-04 08:56:51 · answer #5 · answered by ag_iitkgp 7 · 0⤊ 0⤋
no
2007-04-04 08:46:21 · answer #6 · answered by Anonymous · 0⤊ 0⤋