If the probability that A occurs is .21, the probability that B occurs is .34, and the probability that both occur is .05. What is the probability that A does not occur? Round your answer to two decimal places.
2007-04-04 06:34:46 · 4 answers · asked by Lacie L 1 in Science & Mathematics ➔ Mathematics
p(not A) = 1 - p(A) = 0.79.
2007-04-04 06:54:13 · answer #1 · answered by Anonymous · 0⤊ 0⤋
P(A and B) = .05 = P(A|B)P(B) = P(A|B) .34; so that P(A|B) = .05/.34 which is the probability of A given that B has already occured. In which case, the probability that A does not occur given that B has occured is 1 - P(A|B) = 1 - .05/.34, you can do the math.
I assumed you were looking for P(NOT A|B) rather than P(NOT A) because you did give the joint probability of A and B. If that's not the case, then 1 - P(A) is the answer you are looking for as given by the others.
2007-04-04 07:14:42 · answer #2 · answered by oldprof 7 · 0⤊ 0⤋
Are you sure that you have copied the question correctly?
There seems to be too much information. I would expect the question to have been something like - what is the probability of A or B.
2007-04-04 06:58:00 · answer #3 · answered by Anonymous · 0⤊ 0⤋
0.79
Please give me best answer thanks!
2007-04-04 06:39:57 · answer #4 · answered by Anonymous · 1⤊ 0⤋