If 2.30 L of helium at 21.0 °C is allowed to expand to 6.60 L, with the pressure remaining the same, what is t

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If 2.30 L of helium at 21.0 °C is allowed to expand to 6.60 L, with the pressure remaining the same, what is t

2007-04-04 06:30:33 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry

3 answers

P1V1/T1 = P2V2/T2

Substitute your initial and final values and calculate the one you don't know. Since you don't have a number for P, just insert P and they will cancel. Make sure to express T in K (not celcius).

2007-04-04 06:34:48 · answer #1 · answered by hcbiochem 7 · 0⤊ 0⤋

Use the ideal gas law. P1V1/t1 = P2V2/t2

P1=P2, so: V1/t1 = V2/t2, t2 = V2*t1/V1

t must be absolute temperature, t1=21.0+273.15=294.16

2.30/294.15 = 6.60/t2, t2 = (6.6*294.15/2.30)-273.15 = 570.93 degrees C

2007-04-04 13:59:54 · answer #2 · answered by TiMo 1 · 0⤊ 0⤋

i think its 60.26C

T1/P1=T2/P2

2007-04-04 13:37:00 · answer #3 · answered by justin 1 · 0⤊ 0⤋