The distance d in meters that a ball has dropped at t seconds follows the equation f(t) = 4.9^2. If the ball is dropped from a height of 54 m, find the rate of change of distance with respect to time at 3 s.
2007-04-04 05:36:30 · 5 answers · asked by Laguna B 1 in Science & Mathematics ➔ Mathematics
it's 4.9 t^2...
the height is irrelevant, if it is big enough. fot t=3, the ball is still in the air and the, the speed is 9.8 t so 29.4 m/s.
2007-04-04 05:56:49 · answer #1 · answered by gianlino 7 · 0⤊ 0⤋
Are you missing a variable? Because f(t) = 4.9^2 implies that f(t) is constant.
2007-04-04 12:39:33 · answer #2 · answered by Anonymous · 0⤊ 0⤋
You're f(t) has no t in it. It's just a constant. There's no solution.
2007-04-04 12:39:48 · answer #3 · answered by Gene 7 · 0⤊ 0⤋
Yea,what he said!
2007-04-04 12:44:54 · answer #4 · answered by Anonymous · 0⤊ 0⤋
it equals x..
2007-04-04 12:43:41 · answer #5 · answered by pivotalperson111 3 · 0⤊ 0⤋