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which of the following are the factors of 4b^2-16
a. (2b+4)(2b+4)
B. 2(b-4)(b+4)
c. (2b-2)(2b+4)
d. 4(b-2)(b+2)
for this one i got b and it was wrong

which of the following are the factors of q-q^2+2q-2?
a.(t^2-9)(t^2-9)
b.(t-3)^2(t+3)^2
c.(t-3)(t+3)^2
d.(t-3)(t+3)(t^2+9)
for this one i got b and it was wrong

which of the following is one of the two binomial factors of 6s^2+40s-64?
a. 6s-12
b. 2s-16
c.3s-4
d. s+10
for this one i got b and it was wrong

2007-04-04 05:22:24 · 8 answers · asked by dolly 2 in Science & Mathematics Mathematics

sorry for #2 it is q^3-q^2+2q-2

2007-04-04 05:42:02 · update #1

8 answers

1. d
2. (I don't understand this because you have the variable q in the question and t in the answer choices)
3. c

I'll tell you how to do (1) and (3)
1. Note that it is in the form a^2 - b^2. Something to remember: a^2 - b^2 = (a+b)(a-b)
So, That factors into (2b+4)(2b-4). You can factor out a 2 from both of these terms, leaving you with 2 * 2 * (b+2) * (b-2) or simply 4(b-2) (b+2)

3. Factor this out by beginning with bringing a 2 out of each term. Then, you will have (3s^2 + 20s - 32)2. Now let's factor what's inside.
(3s )(s ). You know for sure it looks like this (since 3 is prime). Also, you will have a (+) and (-) combo. Since the middle term is positive, the difference is 20. Take 8 and 4. You want a relatively large difference, so if you plug in the correct order, you should get 3s-4 as one of the answers.

2007-04-04 05:32:06 · answer #1 · answered by kash 3 · 0 0

4b^2-16 =(2b-4)(2b+4) None of your answers
q-q^2+2q-2 = q(1-q)+2(q-1) = =
=(q-1)(2-q).Also nothing to do with your answers
6s^2+40s-64 = (2s+16)(3s-4) so the factor is(c)

2007-04-04 12:40:27 · answer #2 · answered by santmann2002 7 · 0 0

4b^2 - 16 = (2b)^2 - 4^ so A

-(q^2 -3q+2) = -(q-2)(q-1) ... the choices dont make sense

6s^2+40s-64 = (3s - 4)(2s+16) so C

2007-04-04 12:31:04 · answer #3 · answered by hustolemyname 6 · 0 0

Well none of the answers from the 1st one are correct. the answer is (2b-4) (2b+4). Because 16 is a perfect square, to get -16 you need to multiply a negative times a postive.

2007-04-04 13:02:50 · answer #4 · answered by Anonymous · 0 0

QUESTION 1
FACTOR OUT A "4" FIRST
4(B^2-4)
4(B-2)(B+2)

QUESTION 2
ADD LIKE TERMS THEN MUTLIPY THROUGH BY A -1
Q^2+3Q+2
(Q-1)(Q-2)
THAT ANSWER KEY IS WRONG

QUESTION 3
2(3S^2+20S-64)
2(3S-4)(S+8)

2007-04-04 12:39:08 · answer #5 · answered by GENE D 1 · 0 0

1) D
2) Are you sure you typed the origional question correctly here? Because none of those answers work.
3) C

2007-04-04 12:31:42 · answer #6 · answered by Jenniffer 2 · 0 0

1 B
2 D
3 A

2007-04-04 12:29:55 · answer #7 · answered by Anonymous · 0 0

d for first question second none o 3rd c

2007-04-04 12:37:55 · answer #8 · answered by dwinbaycity 5 · 0 0

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